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Floyd_Warshall.cpp
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76 lines (72 loc) · 1.73 KB
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#include<iostream>
#include<vector>
#include<algorithm>
using namespace std;
const int MAXNUM = 100000;
//打印路径
//Path是前驱子图, i是起点, j是终点
void PrintPath(vector<vector<int>>& Path, int i, int j){
int k = Path[i][j];//i到j最短路径上j的前驱节点
if (k == -1)
return;
else{
PrintPath(Path, i, k);
cout << k << "-->";
PrintPath(Path, k, j);
}
}
//Floyd算法
//W表示邻接矩阵,Path表示前驱子图矩阵
void Floyd_Warshall(vector<vector<int>>& W, vector<vector<int>>& Path){
/**
*令d(i, j, k)为从节点i到节点j的所有节点全部取自集合{1, 2,..., k}的一条最短路径的权重
*动态转移方程为:
* d(i, j, k) = min(d(i, j, k-1), d(i, k, k-1) + d(k, j, k-1)) k >= 1
* = w(i, j) k == 0
*/
int n = W.size();
for (int k = 0; k < n; k++){
for (int i = 0; i < n; i++){
for (int j = 0; j < n; j++){
if (W[i][j] > W[i][k] + W[k][j]){
W[i][j] = W[i][k] + W[k][j];
Path[i][j] = k;//记录路径
}
}
}
}
//求解好了,打印路径
for (int i = 0; i < n; i++){
for (int j = 0; j < n; j++){
if (W[i][j] == MAXNUM){
if (i != j)
cout << "不存在从节点" << i << "到节点" << j << "的最短路径" << endl;
}
else if(i != j){
cout << "从" << i << "到" << j << "的最短路径长度为" << W[i][j] << " 路径:";
cout << i << "-->";
PrintPath(Path, i, j);
cout << j << endl;
}
}
}
}
int main(){
int n, m;//顶点数和边数
cout << "输入顶点数和边数:";
cin >> n >> m;
vector<vector<int>> W(n, vector<int>(n, MAXNUM));//邻接矩阵
//对角线置0
for (int i = 0; i < n; i++)
W[i][i] = 0;
vector<vector<int>> Path(n, vector<int>(n, -1));//前驱子图矩阵
cout << "输入边的起点,终点,权重:" << endl;
int u, v, w;
for (int i = 0; i < m; i++){
cin >> u >> v >> w;
W[u][v] = w;
}
Floyd_Warshall(W, Path);
system("pause");
return 0;
}