Interfaces and types that use conditional types and inheritance no longer assignable

[mtreder]

TypeScript Version: 3.6.0-dev.20190727

Search Terms: conditional, generic, inheritance, variance

Code
Prior to the --strictFunctionTypes compiler flag in the strict suite, this previously worked fine.

type GetPropertyNamesOfType<T, RestrictToType> = { [PropertyName in Extract<keyof T, string>]: [T[PropertyName]] extends [RestrictToType] ? PropertyName : never }[Extract<keyof T, string>];
type GetAllPropertiesOfType<T, RestrictToType> = Pick<T, GetPropertyNamesOfType<Required<T>, RestrictToType>>;

export interface IRequestA<T extends object>{
    getValue(name: keyof GetAllPropertiesOfType<T, string>): string;
    getObject<ObjectType extends object = never>(name: keyof GetAllPropertiesOfType<T, ObjectType>): IRequestA<ObjectType>;
}

interface Base {
    BaseString: string;
    BaseNumber: number;
    BaseObject: Base;
}

interface Derived extends Base {
    DerivedString: string;
    DerivedNumber: number;
    DerivedObject: Base;
}

function main(a: IRequestA<Derived>): void {
    const a1: IRequestA<Base> = a;
    a1.getValue("BaseString");
    a1.getObject<Base>("BaseObject");
}

As the result of a suggestion in Issue 28671 the interface was switch to a type. This worked until TypeScript version 3.5 where the assignment again started to fail when inheritance was involved with T.

type GetPropertyNamesOfType<T, RestrictToType> = { [PropertyName in Extract<keyof T, string>]: [T[PropertyName]] extends [RestrictToType] ? PropertyName : never }[Extract<keyof T, string>];
type GetAllPropertiesOfType<T, RestrictToType> = Pick<T, GetPropertyNamesOfType<Required<T>, RestrictToType>>;

export type IRequestB<T extends object> = {
    getValue(name: keyof GetAllPropertiesOfType<T, string>): string;
    getObject<ObjectType extends object = never>(name: keyof GetAllPropertiesOfType<T, ObjectType>): IRequestB<ObjectType>;
}

interface Base {
    BaseString: string;
    BaseNumber: number;
    BaseObject: Base;
}

interface Derived extends Base {
    DerivedString: string;
    DerivedNumber: number;
    DerivedObject: Base;
}

function main(b: IRequestB<Derived>): void {
    const b1: IRequestB<Base> = b;
    b1.getValue("BaseString");
    b1.getObject<Base>("BaseObject");
}

With some changes I got it to work by switching around the allowed property name list:

type GetPropertyNamesOfType<T, RestrictToType> = { [PropertyName in Extract<keyof T, string>]: [T[PropertyName]] extends [RestrictToType] ? PropertyName : never }[Extract<keyof T, string>];
type GetAllPropertiesOfType<T, RestrictToType> = Pick<T, GetPropertyNamesOfType<Required<T>, RestrictToType>>;

export type IRequestC<T extends object> = {
    getValue<K extends keyof GetAllPropertiesOfType<T, string>>(name: K): string;
    getObject<ObjectType extends object = never>(name: keyof GetAllPropertiesOfType<T, ObjectType>): IRequestC<ObjectType>;
}

interface Base {
    BaseString: string;
    BaseNumber: number;
    BaseObject: Base;
}

interface Derived extends Base {
    DerivedString: string;
    DerivedNumber: number;
    DerivedObject: Base;
}

function main(c: IRequestC<Derived>): void {
    const c1: IRequestC<Base> = c;
    c1.getValue("BaseString");
    c1.getObject<Base>("BaseObject");
}

Expected behavior:
I would expect b to be assignable to b1 in the example above to be able to work with the subset of properties that are specific to the base type.

Actual behavior:
The assignment doesn't work or I need to jump through hoops to make it work.

I don't know if I'm just trying to limp by staying one step ahead of type checker improvements that will again cause me to make changes or possibly disallow me from accomplishing what I'm looking for.

I'm also not sure about the inconsistency in the need to update the getValue method versus getObject.

Playground Link:
Demo

Related Issues:
Issue 28671
Issue 24190

[RyanCavanaugh]

Is this the simplest possible repro?

[mtreder]

I can remove the extra layer of creating a type to pull property names from via keyof, but still see the error.

Reproduction

[mtreder]

This issue sounded related, but I didn't see the error go away when I was using the under dev typescript version:

Issue 31804

[RyanCavanaugh]

@ahejlsberg this looks like a possible incorrect variance measurement. IRequestB should be covariant in T but it's being treated as invariant because of the T[PropertyName] usage in the conditional type, but it seems like the check expression in a conditional isn't really a valid variance measurement site? Not sure

[jack-williams]

I think the issue here is with the simultaneous use of keyof T and T[PropertyName], rather than the conditional type. Repro without conditional types that I think is roughly faithful:

type GetPropertyNamesOfType<T, K extends number> = {
    [PropertyName in keyof T & string]: [T[PropertyName], PropertyName][K]
}[keyof T & string];

type GetAllPropertiesOfType<T, K extends number> = Pick<T, GetPropertyNamesOfType<Required<T>, K> & keyof T>;

export type IRequestB<T extends object, K extends number> = {
    getValue(name: keyof GetAllPropertiesOfType<T, K>): string;
    getObject<ObjectType extends object = never>(name: keyof GetAllPropertiesOfType<T, K>): IRequestB<ObjectType, K>;
}

interface Base {
    BaseString: string;
}

interface Derived extends Base {
    DerivedString: string;
}

function main(b: IRequestB<Derived, 1>): void {
    const b1: IRequestB<Base, 1> = b;
}

Related to #32311 and #32674.

[mtreder]

I think the issue here is with the simultaneous use of keyof T and T[PropertyName], rather than the conditional type. Repro without conditional types that I think is roughly faithful:
type GetPropertyNamesOfType<T, K extends number> = {
[PropertyName in keyof T & string]: [T[PropertyName], PropertyName][K]
}[keyof T & string];

type GetAllPropertiesOfType<T, K extends number> = Pick<T, GetPropertyNamesOfType<Required, K> & keyof T>;

export type IRequestB<T extends object, K extends number> = {
getValue(name: keyof GetAllPropertiesOfType<T, K>): string;
getObject(name: keyof GetAllPropertiesOfType<T, K>): IRequestB<ObjectType, K>;
}

interface Base {
BaseString: string;
}

interface Derived extends Base {
DerivedString: string;
}

function main(b: IRequestB<Derived, 1>): void {
const b1: IRequestB<Base, 1> = b;
}
Related to #32311 and #32674.

The intent in my example was to pull the property names for a property that matches a given data type. The getValue method should only allow specifying a "name" of a property on T that is of type string (i.e. BaseNumber and BaseObject should be excluded). It is also filtering out property names that aren't of type string, but my example doesn't have any property names that aren't strings. The quoted example above looks to be a different way to express Extract<keyof T, string>.

[mtreder]

It is also a need for this to work with a list of objects of a given type. My current workarounds don't seem to allow me to not produce an error.

type GetPropertyNamesOfType<T, RestrictToType> = { [PropertyName in Extract<keyof T, string>]: [T[PropertyName]] extends [RestrictToType] ? PropertyName : never }[Extract<keyof T, string>];
type GetAllPropertiesOfType<T, RestrictToType> = Pick<T, GetPropertyNamesOfType<Required<T>, RestrictToType>>;

export interface IRequestListOfObjects<T extends object>{
	length: number;
	getObject(index: number): IRequestC<T> | undefined;
}

export type IRequestC<T extends object> = {
    getValue<K extends keyof GetAllPropertiesOfType<T, string>>(name: K): string;
    getObject<ObjectType extends object = never>(name: keyof GetAllPropertiesOfType<T, ObjectType>): IRequestC<ObjectType>;
	getListOfObjects<ObjectType extends object = never>(name: keyof GetAllPropertiesOfType<T, ObjectType[]>): IRequestListOfObjects<T>;
}

interface Base {
    BaseString: string;
    BaseNumber: number;
    BaseObject: Base;
	BaseObjectList: Base[];
}

interface Derived extends Base {
    DerivedString: string;
    DerivedNumber: number;
    DerivedObject: Base;
	DerivedObjectList: Base[];
}

function main(c: IRequestC<Derived>): void {
    const c1: IRequestC<Base> = c;
    c1.getValue("BaseString");
    c1.getObject<Base>("BaseObject");
	c1.getListOfObjects<Base>("BaseObjectList");
}

Example

[RyanCavanaugh]

Here's a cough simplified demo that the variance is measured incorrectly relative to a manual instantiation. IRequestC<Base> and IRequestBase should have the same respective relations to IRequestC<Derived> and IRequestDerived.

interface Base {
    BaseString: string;
    BaseObject: Base;
}

interface Derived extends Base {
    DerivedString: string;
    DerivedObject: Base;
}

type GetPropertyNamesOfType<T, RestrictToType> = {
    [PropertyName in keyof T]: T[PropertyName] extends RestrictToType ? PropertyName : never
}[keyof T];

export type IRequestC<T> = {
    getObject: (name: GetPropertyNamesOfType<T, object>) => void;
}

export type IRequestDerived = {
    getObject: (name: GetPropertyNamesOfType<Derived, object>) => void;
}
export type IRequestBase = {
    getObject: (name: GetPropertyNamesOfType<Base, object>) => void;
}

function concreteContravariant(base: IRequestBase) {
    let derived: IRequestDerived = base;
}

function concreteCovariant(derived: IRequestDerived) {
    let base: IRequestBase = derived;
}

function genericContravariant(base: IRequestC<Base>): void {
    const derived: IRequestC<Derived> = base;
}

function genericCovariant(derived: IRequestC<Derived>): void {
    const base: IRequestC<Base> = derived;
}

[jack-williams]

As check types are related bivariantly I would expect that variance measuring going wrong for the check type would make the measured types more assignable, rather than less. (False-negative)

type Alias<T> = [T] extends [number] ? true : false;

interface Foo<T> {
    x: Alias<T>;
}

const a: Foo<number> = { x: true };
const b: Foo<number | boolean> = a; // no error
const shouldBeFalse: false = b.x;

const c: Foo<number | boolean> = { x: false };
const d: Foo<number> = c; // no error
const shouldBeTrue: true = d.x;

Conversely, the extends types is invariant so that usually makes measured types less assignable, rather than more. (False-positive).

type Alias2<T> = [number] extends [T] ? true : false;

interface Foo2<T> {
    x: Alias2<T>;
}

const a: Foo2<number> = { x: true };
const b: Foo2<number | boolean> = a; // error
const shouldbeTrue: true = b.x;

I think trying to get any meaningful measurements from a conditional type is hard. When the true and false types are unrelated then measurements are just wrong because the conditional type cannot be an order preserving function of its outer type parameters.

My concern is that removing measurements for conditional types would be a breaking change for many people that used any as the instantiation for a measured conditional type.